Need help with part A As shown in the figure below, a green bead of mass 65 g si

Question

Need help with part A As shown in the figure below, a green bead of mass 65 g sides along a straight wire. The length of the wire from point to point is 0.800 m, and point is 0.600 m higher than point .A constant friction force of magnitude 0.30 0 N acts on the bead. If the bead is released from rest at point , what is its speed at point ? m/s A red bead of mass 65 g slides along a curved wire , subject to a friction force with the same constant magnitude as that on the green bead. If the green and red beads are released simultaneously from rest at point , which bead reaches point with a higher speed? The green bead the red bead both beads arrive with equal speed

Explanation / Answer

mgh - fd = (1/2)mv^2

(20/1000) (9.8) (.6) - (.01) (.8) == (1/2) (20/1000) (v)^2

Solve for v: v = 3.31 m/s^2

The green bead will reach point B at a higher speed because it traveled a shorter distance, and therefore there was a shorter distance for the frictional force to act.

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