Exercise 10.29 A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up
ID: 1473744 • Letter: E
Question
Exercise 10.29
A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up a hill without slipping, reaching a maximum height of 6.00 mabove the base of the hill. We can model this ball as a thin-walled hollow sphere.
Part A
At what rate was it rotating at the base of the hill?
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Part B
How much rotational kinetic energy did it then have?
Exercise 10.29
A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up a hill without slipping, reaching a maximum height of 6.00 mabove the base of the hill. We can model this ball as a thin-walled hollow sphere.
Part A
At what rate was it rotating at the base of the hill?
= rad/sSubmitMy AnswersGive Up
Part B
How much rotational kinetic energy did it then have?
Explanation / Answer
K.E. initially = 0.5*I*w2+ 0.5*m*v^2
v= w*R
I = 2/3 mR^2
potential energy final = mgH
= 0.426 *9.81 * 6
R= 11.3 cm
0.5*2/3*m*V^2 +0.5* mv^2 = 0.426 *9.81 * 6
0.5*2/3*V^2 +0.5* v^2 = 9.81 * 6
8.40428462155 m/s =V
w=
8.40428462155 / (11.3/100) =74.3742001907 rad/s
rotational K.E. = 0.5* 2/3 *0.426 (11.3/100)^2 * 74.3742001907^2
=10.029744 J
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