Question 12 of 18 sapling learming The figure below is a pressure versus volume

Question

Question 12 of 18 sapling learming The figure below is a pressure versus volume graph where the different curves represent different processes done on a gas. Starting at the origin to point 1, the pressure and volume are increased to 2677 Pa and 4.25 m3 respectively. From 1 to 2 the gas expands at constant pressure to a volume of 7.25 m3. From 2 to 3 the pressure rises to 4246 Pa. And finally from 3 to 4 the gas expands again to 10.17 m3. Using the ranking module, rank the curves from the most positive to the most negative amount of work done on the gas. Most Positive Work 3 Most Negative Work 3-4 0-1 2-3 1-2 What is the total work done on the gas? V (cubic Number 0-4 Previous 3 Give Up & View Solution Check Answer Next Exit Hint

Explanation / Answer

Use equation,

W= P*V

W01 = (P0*V)horizontal  + (P*V)vertical  = 0*V + 0*0 = 0 J

W12 = P1*V = 2677Pa*(7.25-4.25)m^3 = 8031 J

W23 = P*V = 2677Pa*(7.25-7.25)m^3 = 0 J

W34 = P3*V = 4246Pa*(10.17-7.25)m^3 = 12398 J

Thus

W04 = W01 + W12 + W23 + W34 =  0 J + 8031 J  + 0 J + 12398 J  = 20429 J

Rank:  W34 > W12 > W01 = W23

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.