A cart is stuck in the middle of a tug of war between Dana (left) and Sumeer (ri
ID: 1479541 • Letter: A
Question
A cart is stuck in the middle of a tug of war between Dana (left) and Sumeer (right). When Dana is the only one pulling on the cart, a force of 8.0N causes the cart to move to the left with an acceleration of 1.6 m/s2.
a) While Dana is applying the same pull as before, Sumeer comes along and pulls on the cart too. When Sumeer's pull is added the cart moves to the right with an acceleration of 0.6 m/s2 . How hard is Sumeer pulling?
b) While Dana is applying the original amount of pull, Sumeer changes the force he applies so the cart now moves to the left with an acceleration of 0.6 m/s2 . How hard is Sumeer pulling now?
c) While Dana is applying the original amount of pull, Sumeer changes his pull once again so that the cart moves to the left with a constant velocity. How hard is Sumeer pulling now?
d) While Dana is applying the original amount of pull, Sumeer changes his pull yet again so that the cart moves to the left with an acceleration of 1.0 m/s2 . How hard is sumeer pulling now?
Explanation / Answer
A cart is stuck in the middle of a tug of war between Dana (left) and Sumeer (right). When Dana is the only one pulling on the cart, a force of 8.0N causes the cart to move to the left with an acceleration of 1.6 m/s2.
F = ma = 8 N
Mass of the cart m = F/a = 8 / 1.6 = 5 Kg
a) While Dana is applying the same pull as before, Sumeer comes along and pulls on the cart too. When Sumeer's pull is added the cart moves to the right with an acceleration of 0.6 m/s2 . How hard is Sumeer pulling?
Fsameer – F = ma1
Fsameer – F = 5 x 0.6
Fsameer – 8 = 3
Fsameer = 11 N
b) While Dana is applying the original amount of pull, Sumeer changes the force he applies so the cart now moves to the left with an acceleration of 0.6 m/s2 . How hard is Sumeer pulling now?
F - Fsameer = ma2
F - Fsameer = 5 x 0.6
8 - Fsameer = 3
Fsameer = 5 N
c) While Dana is applying the original amount of pull, Sumeer changes his pull once again so that the cart moves to the left with a constant velocity. How hard is Sumeer pulling now?
F - Fsameer = ma3
F - Fsameer = 5 x 0 ( acceleration is zero since velocity is constant)
8 - Fsameer = 0
Fsameer = 8 N
d) While Dana is applying the original amount of pull, Sumeer changes his pull yet again so that the cart moves to the left with an acceleration of 1.0 m/s2 . How hard is sumeer pulling now?
F - Fsameer = ma4
F - Fsameer = 5 x 1
8 - Fsameer = 5
Fsameer = 3 N
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