Oscillations 4 parts. A 16.0- kg block oscillates back and forth along a straigh

ID: 1480090 • Letter: O

Question

Oscillations

4 parts.

A 16.0-kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Its displacement from the origin is given by

PartA What is the oscillation frequency?

PartB What is the maximum speed acquired by the block?

PartC What is the maximum acceleration of the block?

PartD What is the magnitude of x(t) when the block experiences its maximum acceleration?

Thank you!

x(t) = (16.0 cm) cos[( 16.0 rad/s) t + rad]

PartA What is the oscillation frequency?

PartB What is the maximum speed acquired by the block?

PartC What is the maximum acceleration of the block?

PartD What is the magnitude of x(t) when the block experiences its maximum acceleration?

Thank you!

oscillation frequency = 16/(2pi) =2.54647908947 Hz

maximum speed acquired by the block = Aw =16*16 =256cm/s = 2.56 m/s

maximum acceleration of the block = Aw^2 = 16 * (16^2) =4096 cm/s2 = 40.96 m/s2

maximum acceleration is at amplitude= 16 cm =0.16 m

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