The graph shown below is the velocity, in cm\'sec, of an object moving along the

Question

The graph shown below is the velocity, in cm'sec, of an object moving along the x-axis between times t = 0 and t = 5 seconds. Positive velocity indicates motion to the right. At time t = 5, where is the object in relation to its starting position? At time t = 1, how far is the object from its starting position? Roger runs a marathon. His friend Jeff rides behind him on a bicycle and clocks his speed ever,- 15 minutes. Roger starts out strong, but after an hour and a half he is so exhausted that he has to stop. Jeffs data follows. Assuming that Roger's speed is never increasing, give upper and lower estimates for the distance Roger ran during the first half hour, miles (lower estimate) miles (upper estimate) Give upper and lower estimates for the distance Roger ran in total during the entire hour and a half, miles (lower estimate) miles (upper estimate) How often v/ould Jeff have needed to measure Roger's speed in order to find lower and upper estimates within 0.1 mile of the actual distance he ran?

Explanation / Answer

4)

a)

displacement in 5 sec = 2*3 - 3*2 = 0

so the object is at its starting position.

b)

d = 2*1 = 2 cm

c)

d = 2*3 - 3*2 = 0 cm

5)

a)

d = (15/60)*13 + (15/60)*12 = 6.25 miles (upper estimation)

d = (15/60)*(13+12)/2 + (15/60)*(10+12)/2 = 5.875 miles (lower estimatiion)

b)

d = (15/60)*13 + (15/60)*12 + (15/60)*10 + (15/60)*10 + (15/60)*8 + (15/60)*7 = 15 miles (upper estimation)

d = (15/60)*(13+12)/2 + (15/60)*(10+12)/2 + (15/60)*(10+10)/2 + (15/60)*(10+8)/2 + (15/60)*(8+7)/2 + (15/60)*(7+0)/2 = 13.375 miles (lower estimatiion)

c)

t = (0.1/13)*60 = 0.46154 min

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.