You are palling a 5.6 kg object with 10.5 N force at 45 degree with ground which

Question

You are palling a 5.6 kg object with 10.5 N force at 45 degree with ground which is frictional. If acceleration is measured 1.1 m/s2, what frictional coefficient? 18 N oriented in positive x-axis, 8.9 N oriented at 60 degrees with positive x-axis, 5 N oriented in negative y-axis, and 2.0 oriented at 135 degree with positive x-axis, are working on 7.9 kg object. What is the acceleration? Two blocks of masses m1 = 2 kg and m2 = 3 kg are connected by a string. One block(ms) slides on a table and the other (m2) hangs from the string which passes over a pulley. The coefficient of kinetic friction is 0.20, What is acceleration of blocks? A mass m1 is tied to another mass m with a string which runs over a frictionless pulleys. Mass m is hanging above the ground. The acceleration of masses is measured 2.62 m/s2. What is m? Two masses, one is m1 = 2.0 kg and another one m2 = 3.0 kg are connected by a thin string running over a massless pulley. The mass m2 is hanging above the ground and pulley another mass a 57.27 degree ramp with 2.5 m/s2. Calculate mu_k. A skier with a mass of 62.0 kg is sliding down a 25.0 degree snowy slop. Find the coefficient of kinetic friction for the skier if friction is known to be 44.0 N. A stone is thrown straight downward with initial speed of 9.0 m/s from a high of 74 m. What is the time it takes to the ground?

Explanation / Answer

2.) AS WE KNOW NET FORCE = MASS * ACCELERATION

NET FORCE IN HORIZONTAL DIRECTION = 18+8.9cos(60degree) - 2cos(45degree)= 21.036 N

SO ACCELERATION = F/M= 21.036/7.9= 2.66 m/s^2

3.) F= Ma

NET FORCE ON BOTH MASSES IS F= M2*g - u*M1*g =(3*9.8)-(0.20*2*9.8)=25.48 N

SO ACCELERATION a = F/M= 25.48/(2+3)= 5.096 m/s^2

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