A person walks AWAY from a CONVEX mirror. What happens to the IMAGE of the perso

Question

A person walks AWAY from a CONVEX mirror. What happens to the IMAGE of the person? It gets BIGGER and moves CLOSER to the mirror It gets BIGGER and moves AWAY from the mirror It stays the SAME size and distance from the mirror It gets SMALLER and moves CLOSER to the mirror It gets SMALLER and moves AWAY from the mirror A single slit is illuminated by red light (lambda = 650 nm). The angle from the center of the diffraction pattern to the first minimum is found to be, theta=3.8 degree. The light source is changed to a blue/violet laser pointer (lambda = 405 nm). What is theta now? 2.4 degree 3.8 degree 4.1 degree 6.1 degree 8.5 degree A 275 nm thick oil film (n = 1.44) floats on water (n = 1.33). There is air above the oil. An observer views the film from above at normal incidence. For what WAVELENGTH of visible light (lambda = 400 - 750 nm) is constructive interference seen? 416 nm 465 nm 502 nm 528 nm 650 nm VERTICALLY POLARIZED light of intensity 54 W/m^2 passes through two polarizers. The first polarizer has a transmission axis that is at 70 degree to the vertical and the second polarizer has a horizontal transmission axis. What is the INTENSITY of the transmitted light? 0 W/m^2 5.6 W/m^2 13 W/m^2 24 W/m^2 54 W/m^2

Explanation / Answer

62) 1/v + 1/u = 1/f

=> image distance, v = [u / (u - f)]f

As u increases, [u / (u - f)] decreases, so v decreases. So, the image gets closer.

|hi / ho| = v/u = f / (u - f)

As u increases, |hi / ho| decreases, so the image gets smaller.

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