A person walks 35.0^0 north of west for 11.2 km How far due north and how far du

Question

A person walks 35.0^0 north of west for 11.2 km How far due north and how far due east would he have to walk to arrive at the same location? Suppose that a bobcat can jump to a height of 1.50 m. It jumps at an angle of 50.0 degree relative to the horizontal What speed does the bobcat have to leave the ground in order to teach that height? A GM corvette travels due east with a speed of 122 km/hour The raindrops fall dorm vertically with respect to the earth. If the raindrops make an angle of 35.0 degree with the vertical of the car, what is the velocity of the rain with respect to the earth? A football is kicked with an initial speed of 10.2 m/s at an angle of 40.0 degree above the horizontal. It lands on the ground 2.12 s later. Determine the velocity of the football at the pinnacle of its trajectory.

Explanation / Answer

3) d = -11.2*cos(35)i + 11.2*sin(35) j

d = -9.17i +6.424 j

if person return its position d = 0

person walk 6.424 km along south and 9.17 along east

4) H = 1.5 m , theta = 50 degrees

Frfom kinematic equation

H = uy^2/2g

1.5 = (u*sin(50))^2/(2*9.8)

u = 7.078 m/s

5) vre = 122*sin(35) = 70 km/hour

6) ux = vx = 10.2 cos(40) = 7.814 m/s

from kinematic equation

vy = uy+at

vy = 10.2*sin(40) +(9.8*2.12)

vy = 27.33 m/s

v = (7.814^2 +27.33^2)^0.5

v = 28.4 m/s

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