Two small speakers are driven by a common oscillator at 7.05 Times 10^2 Hz. The

Question

Two small speakers are driven by a common oscillator at 7.05 Times 10^2 Hz. The speakers face each other and are separated by d = 1.56 m. Locate the points along a line joining the two speakers where relative minima would be expected. (Use v = 343 m/s. Choose one speaker as a reference and enter your answers as positive distances from this speaker, from smallest to largest. Enter NONE in unused answer boxes.). Your response differs from the correct answer by more than 10%. Double check your calculations.

Explanation / Answer

wavelength = v/f
= 343 / (7.05*10^2)
= 0.487 m

minima occurs when path difference is (2n+1)*wavelength/2

for n= 0
d0 = wavelength/2 = 0.487/2 = 0.243 m

dn = (2n+1)*do
for n= 1
d1 = 3*0.243 = 0.730 m

for n= 2
d1 = 5*0.243 = 1.22 m

for n= 3
d1 = 7*0.243 = 1.7 m
This goes beyond the distance between speakers

Answers are:
0.243 m
0.730 m
1.22 m

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