1. Use the worked example above to help you solve this problem. In a system simi
ID: 1484318 • Letter: 1
Question
1. Use the worked example above to help you solve this problem. In a system similar to that shown in the figure, the gas in the cylinder is at a pressure of 1.01 times 10^5 Pa and the piston has an area of 0.104 m^2. As energy is slowly added to the gas by heat, the piston is pushed up a distance of 4.10 cm. Calculate the work done by the expanding gas on the surroundings, assuming the pressure remains constant Gas in a cylinder similar to the one shown in the figure moves a piston with area 0.198 m^2 as energy is slowly added to the system. If 2.09 times 10^3 J of work is done on the environment and the pressure of the gas in the cylinder remains constant at 1.01 times 10^5 Pa, find the displacement of the piston. delta y = m.Explanation / Answer
work = PdV
A)
dV = area*dH =(0.104)*(4.10/100) m^3
Work = 1.01*10^5 *(0.104)*(4.10/100)
= 430.664 J
B)
work done = pdV
2.09*10^3 = 1.01*10^5 *(0.198)*(h)
h = 0.10451045104 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.