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1. Use the worked example above to help you solve this problem. Suppose a block

ID: 2019731 • Letter: 1

Question

1. Use the worked example above to help you solve this problem. Suppose a block with mass 3.00 kg is resting on a ramp. If the coefficient of static friction between the block and the ramp is 0.360, what maximum angle can the ramp make with the horizontal before the block starts to slip down?

i got 19.8...then, Use that values to help you work this exercise. The ramp in the figure is roughed up and the experiment repeated.

(a) What is the new coefficient of static friction if the maximum angle turns out to be 33.1°?

(b) Find the maximum static friction force that acts on the block.

Explanation / Answer

apply Newton's second law of motion ,    Fx = mg sin - s mgcos = 0               mg sin = s mgcos               tan = s   coefficient of static friction is      s = tan33.1          = 0.651 ......................................................................... maximum static friction is         fs = sFn             = smgcos             = (0.651)(3 kg)(9.8 m/s2)cos33.1            = 16.03 N   coefficient of static friction is      s = tan33.1          = 0.651 ......................................................................... maximum static friction is         fs = sFn             = smgcos             = (0.651)(3 kg)(9.8 m/s2)cos33.1             = smgcos             = (0.651)(3 kg)(9.8 m/s2)cos33.1            = 16.03 N