genetic biology (4) In chickens, the gene for red color (R), shaggy feathers (Sg

Question

genetic biology

(4) In chickens, the gene for red color (R), shaggy feathers (Sgf) and black tail (Bt) appear to be on the same autosome and have the following phenotypes and dominant/recessive relationships (8 points total) R-red body feathers, dominant r- white body feathers, recessive Sgfstraight feathers, dominant sgf - shaggy feathers, recessive Bt - black tail feathers, dominant bt white tail feathers, recessive A random red body, straight feathered, black tail rooster from a pen containing chickens with a mix of phenotypes of red or white body feathers, straight or shaggy feathers, and black or white tails, was crossed to hens from a pen that contained pure-breeding white body, shaggy, white tailed chickens The progeny had the following phenotypes and counts red body, straight feather, black tail white body, straight feather, black tail white body, shaggy feather, black tail white body, shaggy feather, white tail red body, shaggy feather, black tail red body, shaggy feather white tail red body, straight feather, white tail white body, straight feather, white tail 250 310 46 264 37 331 42 34

Explanation / Answer

Recombination in the gene is a important topic in the inheritance biology, with the help of recombination we easily can found the linkage gene, crossing over and the distance between two gene.

Now let's focus on the given statement

There are three gene that is present on the same chromosomes and the organism is diploid and contain Dominent as well as recession character also.

Long distance between 2 gene have greater change of crossing over but in small distance the crossing over is less.

There are three pair of gene that contain Dominent and recessive character.

In the given frequency we can see that there are 2 frequency that contain more opposite character. In these one is :- r Sgf Bt that is 310 and second:- R sgf bt have 331 frequency that don't contain the crossing over and after that R Sgf Bt and r sgf bt have more progeny that contain 1 single crossing over and the distance between gene is much more.

But in the case of R sgf Bt and r Sgf bt have also single crossing over but the two gene is very close so recombination frequency is low.

And the case in r sgf Bt and R Sgf bt have double crossover in the gene.

Now we can calculate the frequency of gene by formula

Recombinant/ Total case× 100

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