Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

26. An 80.0 kg student stands on a 200kg platform and applies a steady downwards

ID: 1485620 • Letter: 2

Question

26. An 80.0 kg student stands on a 200kg platform and applies a steady downwards force .'of 300 Nona long rope, the rope extends up from the students hands, passes over puley #1 at the top and then under pulley #2; finally the rope is attached to the bottom of pulley #1 , as shown in the figure Assume that the ropes and pulleys have negigible mass, and that the puleys are ideal and frictioniess. The top pulley remains at rest T4 Pulley # 1 Pulley # 2 The tension is equal to A. 900 N B 600N C. 300 N D 200N E. 150 N The tension is equal to A. 1800N B. 900 N C. 600 N. D. 300 N E. 150 N The tension T in the top rope is equal to A. 1800N B, 900 N C. 8 600N. D. 300 N. E. 150 N The acceleration of student and platform is equal to A. 0.60 up B. 080 down. c. 300 down. D. 380 up E. 8.20 down. I2 s2 s2 s1 The normal force which the platform exerts on the student's feet has a magnitude of A 1084N B. 784 N. C C. 548 N D. 484N.E. 420 N D. 484 N E. 420 N.

Explanation / Answer

T1 = T2 =T3 = 300 N

T4 = 900 N

F = Ma

980 - 900 = 100*a

a= 0.80 m/s^2

80*9.8 - T - N = 80*0.8

N = 420 N

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote