A glass tube has several different cross-dectional areas with the values indicat
ID: 1486176 • Letter: A
Question
A glass tube has several different cross-dectional areas with the values indicated in the figure. A piston at the left end of the tube exerts pressure so that mercury within the tube flows from the right end with a speed of 8.0m/s. Three points within the tube are labeled A, B, and C.
a) at what speed is mercury flowing past the point labeled A?
b) what is the total pressure at point A?
c) what is the total pressure at point B?
d) Determine the height h of mercury in the vertical tube with the evacuated upper end (meaning it is open to atmospheric pressure).
evacuatod 12.0 cm 5.6 cm2 6.0 cm 8.0m/s 8.0 mis pistonExplanation / Answer
given
vC = 8 m/s
a) use continuty equation
A_A*v_A = A_C*v_C
v_A = A_C*v_C/A_A
= 6*8/12
= 4 m/s <<<<<<<<-------------------Answer
b)
use Bernoulli's theorem
PA + 0.5*rho*V_A^2 = PC + 0.5*rho_v_C^2
PA = PC + 0.5*rho*(v_C^2 - v_A^2)
= 1.013*10^5 + 0.5*13.6*10^3*(8^2 - 4^2)
= 4.277*10^5 pa <<<<<<<<<<----------------Answer
c) use continuty equation
A_B*v_B = A_C*v_C
v_B = A_C*v_C/A_B
= 6*8/5.6
= 8.57 m/s
use Bernoulli's theorem
PB + 0.5*rho*V_B^2 = PC + 0.5*rho_v_C^2
PB = PC + 0.5*rho*(v_C^2 - v_B^2)
= 1.013*10^5 + 0.5*13.6*10^3*(8^2 - 8.57^2)
= 3.707*10^4 pa <<<<<<<<<<----------------Answer
d) we know, PB = rho*g*h
==> h = PB/(rho*g)
= 3.707*10^4/(13.6*10^3*9.8)
= 0.278 m <<<<<<<<<<----------------Answer
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.