Question 13 Two positive charges, Q 1 = 13.0 C and Q 2 = 27.1 C are placed a dis

Question

Question 13

Two positive charges, Q1 = 13.0 C and Q2 = 27.1 C are placed a distance d = 41.7 cm apart as shown in the diagram above.

What is the magnitude of the force experienced by Q1 due to the charge Q2?

F = Answer N

Note: the diagram is not to scale. You can assume the charges are point charges. They are not free to move.

Question 14

A third charge, Q3 = -30.4 C, is placed between the two charges Q1 and Q2. If there is no force on Q3what is the distance between Q1 and Q3?

Distance from Q1 = Answer cm

Explanation / Answer

A charge Q1 = 13 C is a distance r = 41.7 cm away from a charge Q2 = 27.1 C. Calculate the magnitude of the force on Q1 due to Q2.

F = kQq / d² = 8.99x109N·m²/C² ( 13C * 27.1C) / (0.417m)² = 18213.7858

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