Question 13 Two positive charges, Q 1 = 13.0 C and Q 2 = 27.1 C are placed a dis

ID: 1486410 • Letter: Q

Question

Question 13

Two positive charges, Q1 = 13.0 C and Q2 = 27.1 C are placed a distance d = 41.7 cm apart as shown in the diagram above.

What is the magnitude of the force experienced by Q1 due to the charge Q2?

F = ?Answer? N

Note: the diagram is not to scale. You can assume the charges are point charges. They are not free to move.

Question 14

A third charge, Q3 = -30.4 C, is placed between the two charges Q1 and Q2. If there is no force on Q3what is the distance between Q1 and Q3?

Distance from Q1 = ?Answer? cm

13)

the force experienced by Q1 due to the charge Q2 (F12) = kQ1Q2/d2 = 8.98*109*13*27.1/(0.417)2

F12 = 18.193*1012 N

14)

at distance s from Q1, Q3 is placed where no force on Q3 so

F13 = F32

-kQ1Q3/s2 = -kQ3Q2/(d-s)2

13*(41.7 - s)2 = 27.1*(s)2

(41.7 - s)2/s2 = 27.1/13 = 2.085

(41.7 - s)/s = +/- 1.444

if we take + 1.444 then

41.7 - s = 1.444s

s = 41.7/2.444 = 17.0622 cm (this distance from Q1)

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