(a) What is meant by a negative object distance? Describe a specific situation i

Question

(a) What is meant by a negative object distance? Describe a specific situation in which a negative object distance can occur. (Do this on paper. Your instructor may ask you to turn in your work.)

(b) Find the image distance and the magnification for a thin lens in air when the object distance is -23 cm and the lens is a converging lens that has a focal length of 19 cm. Describe the image - is it virtual or real, upright or inverted?

realvirtual     

(c) Repeat Part (b) if the object distance is, instead, -9 cm and the lens is diverging and has a focal length (magnitude) of 30 cm.

realvirtual     

Explanation / Answer

a)

The object distance is considered negative if the incoming light is on the opposite side of the mirror than the object is. It Means the object is virtual. A Virtual object can occur in a two -lens system.

b) From Thin lens equation, s' = fs/(s-f) = (23* (-23))/ -23-23 = 11.5 cm

Lateral Magnification is m = -s’/s =-11.5/-23 =0.5

Real and Erect

c)

s =-9 cm, f= -30 cm

so, s’ = -9*-30/-9-30 = 6.923 cm

Lateral Magnification is m = -s’/s =-6.923/-9 =0.769 cm

Real and erect.

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