(a) What is in Newtons the magnitude of the force acting on the top charge (q 3
ID: 2290347 • Letter: #
Question
(a) What is in Newtons the magnitude of the force acting on the top charge (q3) due to the bottom left charge (q1)?
(b) What is in degrees the direction of the force acting on the top charge (q3) due to the bottom left charge (q1)?
(c) What is in Newtons the magnitude of the force acting on the top charge (q3) due to the bottom right charge (q2)?
(d) What is in Newtons the magnitude of the force acting on the top charge due to the other two charges?
(e) What is in degrees the direction of the force acting on the top charge due to the other two charges?
Express directions in degrees relative to the traditional positive direction and measured in the counterclockwise direction.
Explanation / Answer
part a)
F13=kq1q3/(a2+c2)
part b)
since q1 and q3 are of opposite sign, force will be attractive
so it makes an angle of (90+45)clocwise with line joining q1q2
part c)
F23=kq2q3/(b2+c2)
since this force is also attractive
so its angle is (90+45) counterclockwise from line joining q1 and q2
part d)
net angle between F1 and F2=90 degrees
F12=F1F2
part e)
its direction will be between F1 and F2 but more inclined towards F2 because q2 is greater than q1
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