A mass moving with speed v_0 on a horizontal frictionless surface is fastened by

Question

A mass moving with speed v_0 on a horizontal frictionless surface is fastened by a string to a peg as shown. As the mass moves, it winds up around the fixed peg, causing the mass to follow a spiral path inward. v_0 always remains perpendicular to the string. What is the initial angular momentum and final angular momentum? s angular momentum about the center of the peg conserved? Explain, is energy conserved? Explain. If the speed is v_0 when the string length is l_0, what is the speed when the string length has been reduced to J_0/3?

Explanation / Answer

a. initial angular momentum = mvol

final angular momentum=0 as lo will be zero

b. angular momentum is not conserved

c. energy should be conserved as there is no other option of energy lost.

d. as energy is conserved, speed should remain same i.e. vo

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