The thin glass shell shown in (figure 1) has a spherical shape with a radius of

Question

The thin glass shell shown in (figure 1) has a spherical shape with a radius of curvature of 14.0 cm. and both of its surfaces can act as mirrors. A seed 3.30 mm high is placed 15.0 cm from the center of the mirror along the optic axis, as shown in the figure. calculate the location of the image of this seed Express your answer in centimeters to three significant figures. calculate the height of the images of this seed. express your answer in millimeters to three significant figures. suppose now that the shell is reversed. find the location of the seed's image express your answer in centimeters to three significant figures.

Explanation / Answer

Part A -
Radius of Curvature, R = 14.0 cm
Focal length of a Concave mirror is +ve, f = R/2
f = 14.0/2
f = 7.0 cm

Distance of Object, do = 15.0 cm
Height of the Object, ho = 3.30 mm
Distance of Image, di = ?

We know,
1/f = 1/di + 1/do
1/7.0 = 1/di + 1/15.0
di = 13.125 cm
Location of image of the seed from the mirror, di = 13.25 cm

Part B -
We know,
M = -di/do = hi/ho
- (13.25/15) = hi/3.30 mm
hi = - 2.92 mm
Height of the Image , hi = 2.92 mm

P.S = - ve sign means the image is inverted.

Part C -
Now, Focal Length = - 7.0 cm

1/f = 1/di + 1/do
- 1/7.0 = 1/di + 1/15
di = -4.77 cm

Distance of the Image from the mirror, di = - 4.77 cm

P.S - (-ve sign means the image is located behind the mirror.)

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