The thin glass shell shown in the figure (Figure 1) has a spherical shape with a

Question

The thin glass shell shown in the figure (Figure 1) has a spherical shape with a radius of curvature of 12.0 cm , and both of its surfaces can act as mirrors. A seed 3.30 mm high is placed 15.0cm from the center of the mirror along the optic axis, as shown in the figure.

Part A

Calculate the location of the image of this seed.

Part B

Calculate the height of the image of this seed.

Part C

Suppose now that the shell is reversed. Find the location of the seed's image.

Part D

Find the height of the seed's image.

Explanation / Answer

A) for concave mirror.

f = +R/2 = 6 cm

object distance, do = 15 cm

using mirror equation,

1/f = 1/di + 1/do

1/6 = 1/di + 1/15

di = 10 cm

Image is at 10cm distance from mirro on the same side.

b) Magnification, m = hi/ho = -(di /do)

hi / 3.30 = - (10/15)

hi = - 2.2 mm

so height of image is 2.2 mm (Inverted)

c) now it is convex mirror

so f = - 6 cm

using mirror equation,

1/f = 1/di + 1/do

1/(-6) = 1/di + 1/15

di = - 4.3 cm

Image is at 4.3 cm distance from mirro on the other side.

d) Magnification, m = hi/ho = -(di /do)

hi / 3.30 = - (-4.3/15)

hi = 0.94 mm

so height of image is 0.94 mm (Upright)

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