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The thin glass shell shown in the figure (Figure 1) has a spherical shape with a

ID: 1555175 • Letter: T

Question

The thin glass shell shown in the figure (Figure 1) has a spherical shape with a radius of curvature of 11.5 cm , and both of its surfaces can act as mirrors. A seed 3.30 mm high is placed 15.0 cm from the center of the mirror along the optic axis, as shown in the figure.

Part A

Calculate the location of the image of this seed.

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Part B

Calculate the height of the image of this seed.

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Part C

Suppose now that the shell is reversed. Find the location of the seed's image.

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Part D

Find the height of the seed's image.

s= cm

Explanation / Answer


R = 11.5 cm , y = 3.3 mm , s = 15 cm

pART A:

from mirror formula:

2/R = 1/s +1/s'

2/11.5 = 1/15 +1/s'

s' = 9.32 cm

Part B:

lateral magnification

y'/y = s'/s

y'/3.3 = 9.32/15

y' = 2.05 mm

Part C: R = -11.5 cm

from mirror formula:

2/R = 1/s +1/s'

-2/11.5 = 1/15 +1/s'

s' = -4.16 cm

Part D:

lateral magnification

y'/y = s'/s

y'/3.3 = 4.16/15

y' = 0.915 mm

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