1. The blood speed in a normal segment of a horizontal artery is 0.15 m/s. An ab
ID: 1487081 • Letter: 1
Question
1. The blood speed in a normal segment of a horizontal artery is 0.15 m/s. An abnormal segment of the artery is narrowed down by an arteriosclerotic plaque to one-eighth the normal cross-sectional area. What is the difference in blood pressures between the normal and constricted segments of the artery
2. An airplane wing is designed so that the speed of the air across the top of the wing is 256 m/s when the speed of the air below the wing is 249 m/s. The density of the air is 1.29 kg/m3. What is the lifting force on a wing of area 30.0 m2?
Explanation / Answer
1)
P1-P2 = 1/2 (Rho(V1^2-v2^2)), Rho is density of blood = 1030kg/m3
= 1/2 Rho*(v2A2/1/8*A2)^2 - 1/2 Rho(V2^2)
P1-P2 = 1/2 (Rho(V2^2) (64-1) = 0.5*1060*0.15^2*63 = 751.2 Pa
2)
Area = 30 m^2
= 1.29 kg/m^3
SO: change in pressure is change in KE density
P = (1/2)**(Vt^2-Vb^2)
= (1/2)*1.29*(256^2-249^2) = 2280.075 N/m^2
Lift force = P *Area = 2280.075 N/m^2 *30 = 68402.25 N
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