8. By applying a constant horizontal force of magnitude F, a student pushes a he
ID: 1487598 • Letter: 8
Question
8. By applying a constant horizontal force of magnitude F, a student pushes a heavy box of mass M along the kitchen floor at a constant speed v. The coefficient of kinetic friction between the floor and the box is K, and the coefficient of static friction is S (where S >K). The student then suddenly stops pushing. What can you say about the motion of the box after student stops pushing?
A) The box slows to a stop with constant acceleration of magnitude F/(2M).
B) The box slows to a stop with constant acceleration of magnitude F/(M).
C) The box slows to a stop with constant acceleration of magnitude smaller than F/M but larger than
F/(2M).
D) The box stops instantly after the pushing is stopped. E) The box has a constant speed of v/2.
Explanation / Answer
here,
from newton second law : SUM(F) = 0
F - Ff = 0 (While Pushing)
Where,
F = is applied force
Ff = frictional Force
F = Ff (While Not Pushing)
ma = Ff
Therefore, When applied force is removed the box slows down with a constant acceleration of magnitude F/M
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.