A3) Volume of gas at A is ___ m 3 . (3 pts) B) Process step #1: A-B Pressure, P,

Question

A3) Volume of gas at A is ___ m3. (3 pts)

B) Process step #1: A-B

Pressure, P, is decreased iso-chorically to 1/2 its initial pressure.

B1) Temperature at B is Blank 4 K. (3 pts)

C) Process step # 2: B-C

Volume, V, is increased isobarically from B-C returning to the same temperature as at A.

C1) The volume of the gas at C is ___ m3. (3 pts)

D) Full process: A-B-C

D1) The change in the internal energy of the gas is ___ J (does it increase or decrease) (3 pts)

D2) The work done on the gas for the process A-B-C is __ J (3pts) and is positive or negative ___(1 pts)

D3) An amount of heat Blank 9 flows into or out-of gas

D4) The full process is adiabatic, isothermal , isobaric, or isochoric

Explanation / Answer

Part A

5 kg of N2 gas

number of moles

n = 5000/28 = 178.57 mples

Part B

temperature of gas at a

T = 273 kelvin = 0 degree celcius

Part C

Volume at A

V = nRT/P

V = 178.57 * 8.314*273/1.01*10^5

V = 4.01m^3

Part D

for isochoric process

P1/T1 = P2/T2

P2 = P1/2

so T2 = T1/2 = 273/2

T2 = 136.5 K

Part E

for isobaric process

V1/T1 = V2/T2

temperature doubles so volume also double

V2 = 2V1 = 8.02 m^3

Part F

as gas reach at initial temperature so change in internal energy = 0

Part G

work done is = P*(V2 - V1)

W = 1.01*10^5/2 *(8.02-4.01)

W = 202505 J

work done is positive

Part H

amount of heat

delta Q = total work done = 202505J flow in

Part I

process is isobaric

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