Two charges q1 = -1 nC and q_2 = -3 nC are situated at the diagonal comers of a

Question

Two charges q1 = -1 nC and q_2 = -3 nC are situated at the diagonal comers of a rectangle. What is the magnitude of the electric field E at point C? What is the direction of the electric field vector at the point C? (Present the expression for the angle made by vector E and the x-axis)(Use Figure 1). Show E vector on the diagram. (1 nC = 10^-9 C) Two charges q_1 = -1 nC and q_2 = -3 nC are situated at the diagonal corners A and B of a rectangle ACBD two charges q_1 and q_2 in Figure 1? What is the electric

Explanation / Answer

here,

q1 = - 1 nC

q1 = - 1 * 10^-9 C

q2 = - 3 nC

q2 = - 3 * 10^-9 C

electric feild due to q1 , E1 = - k * q1/1^2 = - 9 * 10^9 * 1 * 10^-9 /1^2

E1 = - 9 i N/C

electric feild due to charge q2 , E2 = k * q2/3^2

E2 = - 9*10^9 * 3 * 10^-9 /3^2 j

E2 = - 3 j N/C

the magnitude of electric feild at C , E = sqrt( E1^2 + E2^2)

E = 9.49 N/C

the magnitude of electric feild is 9.49 N/C

theta = arctan( 3/9)

theta = 18.43 degree

the direction is 198.43 degree counterclockwise from the x axis

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