You’re choreographing your school’s annual ice show. You call for eight 56-kg sk

Question

You’re choreographing your school’s annual ice show. You call for eight 56-kg skaters to join hands and skate side by side in a line extending 13 m . The skater at one end is to stop abruptly, so the line will rotate rigidly about that skater. For safety, you don’t want the fastest skater to be moving at more than 10 m/s , and you don’t want the force on that skater’s hand to exceed 300 N. What do you determine is the greatest speed the skaters can have before they execute their rotational maneuver?

Explanation / Answer

Total moment of inertia = 56 * (1.857 2 + 3.7142 + 5.5712 + 7.4282 + 9.2852 + 11.1422 + 132)

                                      = 27037.296 kg.m2

=>     8 * 1/2 * 56 * v2 = 1/2 * 27037.296 * (10/13)2

=>   v = 5.9758 m/sec              -------------------> greatest speed the skaters can have .

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