The figure below shows a bar of mass m = 0.300 kg that can slide without frictio

Question

The figure below shows a bar of mass m = 0.300 kg that can slide without friction on a pair of rails separated by a distance l = 1.20 m and located on an inclined plane that makes an angle theta = 35.0 degree with respect to the ground. The resistance of the resistor is R = 1.80 Ohm and a uniform magnetic field of magnitude B = 0.500 T is directed downward, perpendicular to the ground, over the entire region through which the bar moves. With what constant speed v does the bar slide along the rails?

Explanation / Answer

here,

resistance, R = 1.80 ohms

length of rod, l = 1.20 m

mass = 0.300 kg

angle of plane, A = 35 degrees

Magnatic field, B = 0.500 T

force along path = force due to field
mgSinA = I*B*L*Sin(90-35)

Solvign for Current, I = mg*Sin35/B*L*Sin55
I = mg*Sin35/B*L*sin55
I = (0.3 * 9.81 * Sin35)/(0.5*1.20*Sin55)
I = 3.435 A

Therefore,
Emf = I*R
B*l*v = I*R

Solving for Velocity of rod, v

v = I*R/B*l
v = 3.435*1.80/(0.5*1.2)
v = 10.305 m/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.