A +16 nC charge is located at the origin. What is the electric field at the posi
ID: 1491052 • Letter: A
Question
A +16 nC charge is located at the origin. What is the electric field at the position (x_1, y_1) = (5.0 cm, 0 cm) ? Write electric field vector in component form. Express your answers using two significant figures. Enter your answers numerically separated by a comma. What is the electric field at the position (x_2, y_2) = (-5.0 cm, 5.0 cm) ? Write electric field vector in component form. Express your answers using two significant figures. Enter your answers numerically separated by a comma. What is the electric field at the position (x_3, y_3) = (-5.0 cm, -5.0 cm) ? Write electric field vector in component form. Express your answers using two significant figures. Enter your answers numerically separated by a comma.Explanation / Answer
1) The electric field due to a point charge is given by the following:
E = Q / (4 * pi * e0 * r^2) , where e0 is epsilon , Q is the charge, and r is the distance from the point charge.
You are given Q = 16 nC = 16 * 10^ -9 C. To answer the first question, you must find the distance from the origin to each of the points given, then plug into the equation of the electric field above. I will help you find r, but it is up to you to plug in and calculate the E field.
***Note: 1 / (4 * pi * e0 ) = 9 * 10^9 Nm^2 / C^2
Remember to convert everything to meters first:
(x, y) = (5.0, 0.0 cm) = ( 0.05, 0 m) so r = sqrt[ x^2 + y^2 ] = .05 m.
Plug this in and calculate E. .
(x, y) = ( -5.0, 5.0 cm) = ( -0.05 , 0.05 m). So r = sqrt[ x^2 + y^2 ] = .07 m.
(x, y) = ( 5.0, -5.0 cm)
he formula you need is coulombs law E=kQ/r^2
k=8.98 *10^9
Q= +15 nC = 15 * 10^(-9) C
r = 5 cm = .05 m
for the x component for E = (8.98 * 10^9)(15 * 10^-9) / (.05)^2 = 53880 N/C
for y component E is 0 because it is r is 0 cm
so part A = (53880, 0) N/C
Repeat using the respective x and y coordinated for part b and c
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.