A simple pendulum is 0.42 m long. At t = 0 it is released from rest starting at

Question

A simple pendulum is 0.42 m long. At t = 0 it is released from rest starting at an angle of 10degree. Ignoring friction, what will be the angular position of the pendulum at t = 0.35 s? Express your answer to two significant figures and include the appropriate units. Part B Ignoring friction, what will be the angular position of the pendulum at t = 3.45 s? Express your answer to two significant figures and include the appropriate units. Part C Ignoring friction, what will be the angular position of the pendulum at t = 6.00 s? Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

here,

theta0 = 10 degree

L = 0.42 m

theta = theta0 * sin(sqrt(g/L) * t)

A)

at t = 0.35 s

theta = 10 * sin(sqrt(9.8/0.42) * 0.35 )

theta = 9.23 degree

B)

at t = 3.45 s

theta = 10 * sin(sqrt(9.8/0.42) * 3.45 )

theta = - 8.18 degree

C)

at t = 6 s

theta = 10 * sin(sqrt(9.8/0.42) * 6 )

theta = - 6.51 degree

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