A 55- kg skier starts from rest at the top of a ski jump, point A in the figure
ID: 1492482 • Letter: A
Question
A 55-kg skier starts from rest at the top of a ski jump, point A in the figure (Figure 1) , and travels down the ramp. Take that h= 40m.
Part A
If friction and air resistance can be neglected, determine her speed vBwhen she reaches the horizontal end of the ramp at B.
.
Express your answer to two significant figures and include the appropriate units.
Part B
Determine the distance s to where she strikes the ground at C.
Express your answer to two significant figures and include the appropriate units.
Explanation / Answer
part A:
as friction and air resistance is neglected, energy conservation principle can be applied.
consider the motion from point A to point B.
initial total energy at point A=potential energy at A+kinetic energy at A
=mass*g*height+0.5*mass*speed^2
=55*9.8*40+0.5*55*0^2
=21560 J
final total energy at point B=potential energy at B+kinetic energy at B
=mass*g*height+0.5*mass*speed^2
=55*9.8*4.4+0.5*55*vB^2
=2371.6 + 27.5*vB^2
equating the two energy values:
21560=2371.6+27.5*vB^2
==>vB=26.415 m/s
part B:
consider the motion from B to C:
initial velocity at point B is 26.415 m/s , along horizontal direction.
let us consider x axis along the 30 degree incline and y axis along perpendicular to the incline.
then component of vB along x axis=vB*cos(30)=22.8761 m/s
component of vB along y axis=vB*sin(30)=13.2075 m/s
acceleration due to gravity along x axis=g*sin(30)=4.9 m/s^2
acceleration due to gravity along y axis=-g*cos(30)=-8.487 m/s^2
when the skier reaches point C, distance travelled along y axis =4.4/cos(30)=5.08068 m
as this distance travelled along -ve y axis, displacement=-5.08068 m
let time taken be t.
then using the formula:
displacement=initial velocity along y axis*time+0.5*acceleration along y axis*time^2
==>-5.08068=13.2075*t-0.5*8.487*t^2
==>t=3.45858 seconds
then distance travelled along x axis=initial velocity along x axis*time+0.5*acceleration along x axis*time^2
=22.8761*3.45858+0.5*4.9*3.45858^2=108.425 m
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