In the photoelectric effect, a packet of light (photon) strikes a metal and give

Question

In the photoelectric effect, a packet of light (photon) strikes a metal and gives all of its energy to one electron. Shows a photon hitting a metal surface and an electron coming out As long as electron gets enough energy from the photon, it can escape from the metal. Suppose a photon with an energy of 2.60 eV strikes a piece of metal. If the electron that it hits loses 1.64 eV leaving the metal, what is the kinetic energy of the electron once it has broken free of the metal surface? Tries 0/10 Suppose an electron breaks from free from a metal surface with a kinetic energy of 0.870 eV. If it lost 0.630 eV of energy leaving the metal, what was the energy of the photon absorbed?

Explanation / Answer

(a)

the kinetic energy is difference between total energy and work function.

KE = E - workfunction
KE =2.60 - 1.64

= 0.96 eV

( b )

here, we need to calculate the total energy.
KE = E - workfunction

E= KE+ workfunction

   = 0.870 eV+0.630 eV

=1.50 eV

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