In the photo-electric effect, the minimum energy required for a single photon to

Question

In the photo-electric effect, the minimum energy required for a single photon to be able to free an electron is called the work function, which we will denote as. a) If = 2.28 eV for a particular target, what is the maximum wavelength that a photon can have while still being able to free an electron from the target? b) What would be the kinetic energy of the electron that is freed by the photon in part a)? c) If we double the frequency of the photon from part a), what would be the kinetic energy of the freed electron?

Explanation / Answer

a)

work function = hc/wavelength

wavelength = hc/workfunction

substituting values we get

wavelength = 544 nm

b)

zero J

c)

if we double frequency

wavelength will become half

so

kinetic enegy will be 2.28eV

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