In an amusement park ride called The Roundup, passengers stand inside a 19.0 m -
ID: 1495874 • Letter: I
Question
In an amusement park ride called The Roundup, passengers stand inside a 19.0 m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane, as shown in the figure (Figure 1). A) Suppose the ring rotates once every 4.30 s . If a rider's mass is 51.0 kg , with how much force does the ring push on her at the top of the ride? B)Suppose the ring rotates once every 4.30 s . If a rider's mass is 51.0 kg , with how much force does the ring push on her at the bottom of the ride?
Explanation / Answer
given
R = 19/2 = 9.5m
m = 51kg
w = 2xpi/4.3 = 1.4612 rad/sec
A)
at the top
N = mw^2 R - mg
N = 534.658 N
B)
at the bottom
N = mw^2R + mg
N = 1534.258 N
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