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In an amusement park ride called The Roundup, passengers stand inside a 19.0 m -

ID: 1495874 • Letter: I

Question

In an amusement park ride called The Roundup, passengers stand inside a 19.0 m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane, as shown in the figure (Figure 1). A) Suppose the ring rotates once every 4.30 s . If a rider's mass is 51.0 kg , with how much force does the ring push on her at the top of the ride? B)Suppose the ring rotates once every 4.30 s . If a rider's mass is 51.0 kg , with how much force does the ring push on her at the bottom of the ride?

Explanation / Answer

given

R = 19/2 = 9.5m

m = 51kg

w = 2xpi/4.3 = 1.4612 rad/sec

A)

at the top

N = mw^2 R - mg

N = 534.658 N

B)

at the bottom

N = mw^2R + mg

N = 1534.258 N

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