In an action-adventure film, the hero is supposed to throw a grenade from his ca

Question

In an action-adventure film, the hero is supposed to throw a grenade from his car, which is going 90.0 km/h. to his enemy's car which is going 110 km.h. The enemy's car is 15.8m in front of the hero's when he lets go of the grenade. If the hero throws the grenade so its initial velocity relative to him is at an angle of45oabove the horizontal, what should the magnitude of the initial velocity be? The cars are both traveling in the same direction on a level road. You can ignore air resistance. Find the magnitude of the velocity both relative to the hero and relative to the earth?

Explanation / Answer

Hero's car speed ( vhero) = 90.0 km/h.=25.0  m/s
Enemy's car speed (v enemy )  =  110km.h  = 30.56  m / s
Separation  (R ) = 15.8 m
Projectile angle (q)  =  450
 Let  themagnitude of the initial velocity be  ' V '
   R=V2sin20/2g 
          
or,               V  =  17.60  m / s
The magnitude of thevelocity relative to the hero
               v   =  ( V -  vhero) 
                     = 7.4  m / s

The magnitude of thevelocity relative to the earth 
               v   =  ( V -  0.0) 
                     = 17.60   m / s.

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