an alpha particle (4He) strikes a stationary uranium nucleus (235U) head-on and

Question

an alpha particle (4He) strikes a stationary uranium nucleus (235U) head-on and elastically. what fraction of the alphas kinetic energy is transferred to the uranium? an alpha particle (4He) strikes a stationary uranium nucleus (235U) head-on and elastically. what fraction of the alphas kinetic energy is transferred to the uranium? an alpha particle (4He) strikes a stationary uranium nucleus (235U) head-on and elastically. what fraction of the alphas kinetic energy is transferred to the uranium?

Explanation / Answer

From the conserve the momentum,

4v=235v1 + 4v2

             v=59v1 + v2

use co-efficient of restitution as e=1

1 = (v1 - v2)/v

Solve the above two equations,

            v1 = 2/59 v

Therefore, the ratio of kinetic energies is,

(KEuran / KE) = [(0.5 x235 x ((2/59)v)2]/ [ 0.5 x4x v2]

            = 0.068/2 =0.0337 ~ 0.034

           

Therefore, 3.4% of K.E is transferred.

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