Two 12.0-cm-diameter electrodes 0.59 cm apart form a parallel-plate capacitor. T

Question

Two 12.0-cm-diameter electrodes 0.59 cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 15 Vbattery.

A) What is the charge on each electrode after insulating handles are used to pull the electrodes away from each other until they are 1.4

cm apart? The electrodes remain connected to the battery during this process.

B) What is the electric field strength inside the capacitor after insulating handles are used to pull the electrodes away from each other until they are 1.4

cm apart? The electrodes remain connected to the battery during this process.

Explanation / Answer

a)

here by using the formula

C = e0 * A / d

C = 8.854 * 10^-12 * pie * 0.06^2/ 0.014

C = 7.15 * 10^-12 F

then

Q = C * V

Q = 7.15 * 10^-12 * 15 = 107.25 * 10^-12 C

b)

E = V / d

E = 15 / 0.014 = 1071.42 V/m

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.