horizontal surface an L-shaped conductr shown \" the figure meves xapndof10matan

Question

horizontal surface an L-shaped conductr shown " the figure meves xapndof10matanangle of a stationary L-shaped conductor i, a uniform 0.10-T mpetic field anim "gu 45I moves along a shaped loop. A11 s the verices of the conductors overlap so thut a) c the ininial emclosed ares is nero 2 pts) What is the direction of the induced cument C Clock wise (4Use Farady's La" to find an espressionforE , b) andthe induced crest inthe loop dt 1) (4) The resistance/vr inter ofthe wires is!"0D10 .. Use thistoevluR1n1Kt-0.10s. 2. A groen laser beam (-530 m) has a power of 1.2 mW and is focused to a beam with a Giamter of 20 mm a) (2 pts) Find the intensity of the laser beam b) (4 ps) Determine the maximum valaes of the elecoric and maghetie ficlds of the dtrogti bea. cj (4 Assuming the beanis sinssoidaland travelingintheydnections mise-felip annd i the x-direction, wrile Ely33 and Bg) in vector otaion 2

Explanation / Answer

a)

as the flux in creaseing

the induced field is into the page

so the current is in clockwise

induced emf is in clockwise

+++++++++++++++++++++

b)

distance travelled in t time = vt

length of the square = x = vt*cos45

area of the square = x^2 = v^2*t^2(cos45)^2

magnetic fleux phi = B*A

emf = rate of change in flux

cos45 = 1/sqrt2

E = B*A/t = B*v^2*t/2

+++++++++

c)

E = 0.1*10^2*0.1/2 = 0.5 V

resistacne R = x*0.01 = v*t*0.01 = 10*0.1*0.01 = 0.01 ohms

I = E/R

I = 0.5/0.01 = 50 A

++++++++++++++++++++++++++

2)

intensity I = P/A = P/(4*pi*r^2)

r = radius = d/2 = 1mm = 10^-3 m

I = 1.2*10^-3/(4*pi*10^-6) = 95.5 W/m^2

(b)

Intensity I = E^2/(2*uo*c)

95.5 = E^2/(2*4*pi*10^-7*3*10^8)

E = 268.3 V

B = E/c = (268.3/(3*10^8)) = 8.94*10^-7 T

(c)

Ey = E*cos(wt)

By = B*sin(wt)

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