homework help Problem 9.43 - MC Part A The figure is a graph of the normal force

Question

homework help

Problem 9.43 - MC Part A The figure is a graph of the normal force exerted by the floor orn a woman making a vertical jump At what time does the woman's feet leave the ground? Hints t= 10.21 Submit My Answers Give Up Incorrect; Try Again Figure 1 of 1 n(N) Part B At what speed does she leave the ground? Hint: The force of the floor is not the only force imparting an impulse to the woman. (Figure 1) 2500 Express your answer using three significant figures Hints 500 t(s) 0.2 0.4 0.5 U= 10.29 m/s Submit My Answers Give Up

Explanation / Answer

A] Woman's feet leave the ground when the normal force becomes zero. This happens at t = 0.5 seconds.

B] Normal force before the jump = 500 N

therefore, m = 500/9.8 = 51.020 kg

Work done = (1/2)(2500+500)(0.4 - 0.2) + (1/2)(0.5 - 0.4)(2500) = 425 J

so, by conservation of energy,

425 = (1/2)mv2

=> v = 4.082 m/s.

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