A horizontal 4.5 mW laser beam that is vertically polarized is incident on a pol

Question

A horizontal 4.5 mW laser beam that is vertically polarized is incident on a polarizing sheet that is oriented with its transmission axis vertical. Behind the first sheet is a second sheet that is oriented so that its transmission axis makes an angle of 20° with respect to vertical. What is the power of the beam transmitted through the second sheet?

A horizontal 4.5 mW laser beam that is vertically polarized is incident on a polarizing sheet that is oriented with its transmission axis vertical. Behind the first sheet is a second sheet that is oriented so that its transmission axis makes an angle of 20° with respect to vertical. What is the power of the beam transmitted through the second sheet? m W

Explanation / Answer

relationship between the initial and final intensity of light.

I = Iocos^2()

The equation for wave intensity can apply to both the initial and transmitted intensity:

I = P/A

Io = Po / A

Assuming the area of the beam does not change, the first equation becomes:

P = Pocos^2()

Solve for the power of the beam as it emerges from the filter. Since the filter's axis is 20 degrees from the horizontal, the angle between the electric field and the filter axis = 90 – 20 = 70 degrees

P = (4.5 x 10^-3 W)cos^2(70)

P = 5.264 x 10^-4 W

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