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A 1.00-kg glider attached to a spFind theg with a force constant 16.0 N/m oscill

ID: 1503210 • Letter: A

Question

A 1.00-kg glider attached to a spFind theg with a force constant 16.0 N/m oscillates on a frictionless, horizontal air track. At t = 0, the glider is released from rest at x = -3.20 cm (that is, the spFind theg is compressed by 3.20 cm). Find the period of the glider's motion. Find the maximum values of its speed and acceleration., Write down the equation for x(t) and then think about how to find the velocity as a function of time from this equation, m/s Note that the original displacement is given in cm, but the acceleration is to be given in m/s. m/s^2 Find the position, velocity, and acceleration as functions of time. (Where position is in m, velocity is in m/s, acceleration is in m/s2, and t is in s. Use the following as necessary: t.)

Explanation / Answer

frequency , w = (k/m)^0.5 = (16.0/1)^0.5 = 4 Hz

a) time period , T = 2*pi/w = 1.57 sec

b) amplitude, A = 3.20 cm = 0.032 m

Vmax = Aw = 0.032*4 = 0.128 m/s

maximum acceleration , a = Aw^2 = 0.032*(4)^2 = 0.512 m/s^2

c) x(t) = -3.20cos(4t) cm

v(t) = 12.8sin(4t) cm/s

a(t) = 51.2cos(4t) cm/s^2