A 1.00-kg beaker containing 2.33 kg of oil (density = 916 kg/m 3 ) rests on a sc

Question

A 1.00-kg beaker containing 2.33 kg of oil (density = 916 kg/m3) rests on a scale. A 2.18-kg block of iron is suspended from a spring scale and is completely submerged in the oil (see figure below). Find the equilibrium readings of both scales.

Please show calculations. Thank you.

top scale     N bottom scale N


A 1.00-kg beaker containing 2.33 kg of oil (density = 916 kg/m3) rests on a scale. A 2.18-kg block of iron is suspended from a spring scale and is completely submerged in the oil (see figure below). Find the equilibrium readings of both scales.

Explanation / Answer

Vi = Mi/?i = 2/7860 = .254E-3 m^3

Fbi = g*Vi*?o = 9.8*.254E-3*916 = 2.284 N

1) Spring scale force Fss = Mi*g - Fbi = 2*9.8 - 2.284 = 17.316 N

2) Lower scale reading Fs1 = g*(Mb + Mo) + Fbi = 9.8*(1+2) + 2.284 = 31.684 N

Check:
(Fs1 + Fss)/g = 5 kg, the total mass of oil, beaker & iron. ?

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