In the figure, a metal rod is forced to move with constant velocity along two pa

Question

In the figure, a metal rod is forced to move with constant velocity along two parallel metal rails, connected with a strip of metal at one end. A magnetic field of magnitude B = 0.376 T points out of the page, (a) If the rails are separated by 32.0 cm and the speed of the rod is 50.7 cm/s, what is the magnitude of the emf generated In volts? (b) If the rod has a resistance of 14.9 Omega and the rails and connector have negligible resistance, what is the current in amperes in the rod? (c)At what rate is energy being transferred to thermal energy? V A Number Units

Explanation / Answer

Here the EMF is equal to the rate of change of flux through the coil.

So, for part (a): EMF is given by E = BVL = 0.376*0.507*0.32 = 0.061 V

(b) Now the current is E/R = 0.061 / 14.9 = 0.0041 A

(c) Rate at which energy is being transferred to thermal energy = I^2*R = 0.0041^2*14.9 = 0.00025 W

Or you may say this as 0.00025 J/s.

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