The figure shows a conducting rod moving over a conducting frame which has a con

Question

The figure shows a conducting rod moving over a conducting frame which has a connection with resistance R = 5.0 Ohm at its left end. The rod itself and the tracks have no resistance. A uniform magnetic field B = 0.9 T is directed into the plane. Use the values v = 4 m/s and w = 25 cm. (a) Find the EMF |epsilon| induced in the circuit (the circuit is on the left of the moving bar). (b) Find the current I in the circuit. (c) Is the currcnt I clockwise or counterclockwise? (d) Find the force F_app (magnitude and direction; to the right or the left) that has to be applied to the bar to move it to the right at the given constant velocity v.

Explanation / Answer

a) Induced emf, = d/dt = B(dA/dt) = Bvw = 0.9 * 4 * 0.25 = 0.9 A

b) Induced current, I = /R = 0.9 / 5 = 0.18 A

c) Since the area of the loop is increasing, magnetic flux is increasing through the loop. So, current will be counter clockwise to oppose this increase in flux.

d) Fapp = = -Fmagnetic = -BIw = -0.9 * 0.18 * 0.25 = -0.04 N

Negative sign indicates this force should be applied opposite to the magnetic force on the conductor. Since the magnetic force is to the left, Fapp is to the right.

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