Find the capacitor\'s potential difference and charge after the insertion An ini

Question

Find the capacitor's potential difference and charge after the insertion

An initially uncharged air-filled capacitor is connected to a 5.53-V charging source. As a result, 7.55 times 10^-3 C of charge is transfered from one of the capacitor's plates to the other. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant of this substance is 7.31. Find the capacitor's potential difference and charge after the insertion. Potential difference after insertion of dielectric: Charge after insertion of dielectric:

Explanation / Answer

capacitor potential difference will not change since both charge and capacitance becomes 7.31 times.

so capacitor potential difference is 5.53 V

and charge is 7.31*7.55*10^-5=55.19 *10^-5

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