A uniform, 246-N rod that is 2.08 m long carries a 225-N weight at its right end

Question

A uniform, 246-N rod that is 2.08 m long carries a 225-N weight at its right end and an unknown weight W toward the left end (see the figure (Figure 1) ). When W is placed 47.9 cm from the left end of the rod, the system just balances horizontally when the fulcrum is located 65.1 cm from the right end.

A) Find W

B) If W is now moved 24.7 cm to the right, how far must the fulcrum be moved to restore balance?

C) If W is now moved 24.7 cm to the right, in what direction must the fulcrum be moved to restore balance?

Figure 1 of 1

Explanation / Answer

65.1 cm = 0.651 m

225__0.651____(fulcrum)__24.7__(246)___...

(225 x 0.651 ) = ( 246 x .247) + W(0.651)

W = 131.66 N

b)

Reaction at the fulcrum = 131.66 + 225 + 246 = 602.66 N

We will take moment about left

Distance of fulcrum from left is x

(602.66)(x) = (246*1)+(225*2.08)+(131.66*0.651)

x = 1.3269682 m

Fulcrum was 1.13 m from left

It must be moved 0.1969682 m to the righ

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