Question
help me with 14.36
When the object is displaced 0.600m to the right of its equilibrium position. It has a velocity of 2.20 m/s to the right and an acceleration of 8.40 m/s^2 to the left. How much farther from this point will the object move before it stops momentarily and then starts to move back ton the left? A. 200-kg frictionless block is attached to an ideal spring with force constant 315 N/m. Initially the spring is neither stretched nor compressed, but the block is moving in the negative direction at 12.0m/s. Find (a) the amplitude of the motion, (b) the block's maximum acceleration, and (c) the maximum force the spring exerts on the block. A. 200-kg frictionless block is attached to an ideal spring with force constant 315 N/m is undergoing simple harmonic motion. When the block displacement +0.200m, it is moving in the negative x-direction with a speed of 4.00 m/s. Find (a) the amplitude of the motion, (b) the block's maximum acceleration, and (c) the maximum force the spring exerts on the block. A mass is oscillating with amplitude A at the end of the spring. How far (in terms of A) is this mass from the equilibrium position of the string when the elastic potential energy equals the kinetic energy? Application of simple Harmonic Motion A 175 g gilder on a horizontal, friction air track is attached to a fixed ideal spring with force constant 155 N/m. At the instant you made measurements on the gilder, it is moving at 0.815 m/s and is 3.00 cm from its equilibrium point. Use energy conservation to find (a) the amplitude of the motion and (b) the maximum speed of the gilder, (c) What is the angular frequency of the oscillations? A proud deep-sca fisherman hangs a 650-kg fish from an ideal spring having negligible mass. The fish stretches the spring 0.180m. (a) Find the force constant of the spring. The fish is now pulled down 5.00 cm and released. (b) What is the period of oscillation of the fish? (c) What is the maximum speed it will reach? A thrill-seeking eat with mass 4.00 kg is attached by a harness to an ideal spring of negligible mass and oscillates vertically in SHM. The amplitude is 0.050 m, and at the highest point of the motion the spring has its natural unstretched length. Calculate the elastic potential energy of the spring (take it to be zero for the unstretched spring), the kinetic energy of the
Explanation / Answer
elastic energy = KE
and total energy = elastic PE + KE
k A^2 / 2 = 2 (Elastic PE)
k A^2 /2 = 2 (k x^2 /2 )
x = sqrt [ A^2 / 2] = 0.707 A
