help me with 8.42. please. may you please show step by step calculation with uni
ID: 1514005 • Letter: H
Question
help me with 8.42. please.
may you please show step by step calculation with units.
direction 24.0 east ol north. Calculate the speed of each vehicle before the collision. The collision occurs during a heavy rainstorm; ignore friction forces af ween the vehicles and the wet road. 8.42 A 5.00-g bullet is fired horizontally into a 1.20-kg the block resting on a horizontal surface. The coefficient of mi kinetic friction between block and surface is 0.20. The bullet Co remains embedded in the block, which is observed to slide 0.310 m 8.4 along the surface before stopping. What was the initial speed of the bullet? wa the 8.43 " A Ballistic Pendulum. A 12.0-g rifle bullet is fired Se with a speed of 380 m/s into a ballistic pendulum with mass fra 6.00 kg. suspended from a cord 70.0 cm long (see Example 8.8 in a d Section 8.3). Compute (a) the vertical height through which the exp pendulum rises, (bj the initial kinetic energy of the bullet, and man te) the kisetic energy of the bullet and pendulum immedistely tol after the bullet becomes embedded in the wood 8.5 8.44 Combining Conservation Laws. A 150-kg block is at ing and is resting on a fritionless horizontal table (Fig. E8.44). tos tached to a very light horizontal spring of force constant 500.0 N/m of an of thi Figure E8.44 of 12 of on nucleu 150 kgExplanation / Answer
Given:
m1 = 0.005 kg (SI unit)
m2 = 1.2 kg
u2 = 0.0 m/s
= 0.2
d = 0.23 m
g = 9.81 m/s^2
Solve for the post-impact initial system velocity
v2 = SQRT [2gd]
v2 = SQRT [ 2 * (0.2) * (9.81 m/s^2) * (0.23 m) ]
v2 = SQRT [ 0.90252 m^2/s^2 ]
v2 = 0.95 m/s
Now find original
u1 = { [m1+m2] * v2 } / [m1]
u1 = { [ (0.005 kg) + (1.2 kg) ] * (0.95 m/s) } / [ 0.005 kg ]
u1 = { [ 1.205 kg ] * (0.95 m/s) } / [ 0.005 kg ]
u1 = { 1.14475 kg-m/s } / [ 0.005 kg ]
u1 = 228.95 m/s
ans- Initial velocity is 228.95 m/s
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