can some one please help me with this I\'m struggling . I have no clue how to th

Question

can some one please help me with this I'm struggling . I have no clue how to this cross. It has given me the blues. I don't understand

10. Diagram the cross that resulted in the dihybrid F, kernels that you tabulated in Table 1.6 using R as the dominant allele for purple and r as the recessive allele for yellow kernels & Su as the dominant allele for starchy [smooth) and su as the recessive allele for sweet [wrinkled] kernels Your diagram must include e Genotypes and phenotypes of P, parents assuming true-breeding (homozygous) parents were used in the cross Purple, Starchy x Yellow, Sweet . P, gametes from each parent . Genotypes and phenotypes of F . Fi gametes . Genotypes, phenotypes, and ratio of F

Explanation / Answer

According to the information, the ratio of phenotypes of the cross lie in the range of nearly 9:3:3:1 which is the standard Mendelian ratio for a dihybrid cross. This type of dihybrid cross ratio is obtained when true-breeding parents of dominant and recessive allele types are crossed with each other. According to the information, the phenotypes being considered here are kernel shape and color. The answers can be found as below:
Genotype of parents, P: RRSS and rrss

Gametes of parents: RS, RS and rs, rs

F1 Genotype: All RrSs

F1 phenotype: All dominant type

F2 cross: Between RrSs and RrSs

F2 phenotype: 9:3:3:1

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